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If i haven't taken calculus should i attempt to take the PCAT test or not?? because it is 22% of the test??? any suggestions
You should check out those self-help books. I haven't looked at a Calculus book in a year and a half, so I DEFINITELY need some reviewing myself. Do a search in the PCAT forum and type in 'calculus'. You'd be surprised with the results.If i haven't taken calculus should i attempt to take the PCAT test or not?? because it is 22% of the test??? any suggestions
I think you should still take it. From what I remember from the test, the calc was very very basic, like first derivaties and integrals, stuff you can learn in one study session.
As for trig/geometry...
You should check out those self-help books. I haven't looked at a Calculus book in a year and a half, so I DEFINITELY need some reviewing myself. Do a search in the PCAT forum and type in 'calculus'. You'd be surprised with the results.
I think you should still take it. From what I remember from the test, the calc was very very basic, like first derivaties and integrals, stuff you can learn in one study session.
As for trig/geometry...
Help me to solve this problem:
1. Determine the probability of having 1 girl and 3 boys in a 4-child family. (Answer 1/4)
To go through all the possibilities that can happen assuming each child comes through a separate birth:
B-B-B-B= 1
G-B-B-B = 4
B-G-G-G = 4
B-B-G-G = 6
G-G-G-G = 1
4/16 = 1/4
easier way i think this is correct is to use the combination formulaCan you explain how you got 1, 4, 4, 6, 1?
Can you explain how you got 1, 4, 4, 6, 1?
easier way i think this is correct is to use the combination formula
so 4!(#of people in family)/ (3!(since there are 3 boys that are indistinguishable)) and you will get 4 diffrent combinations then u can ask ur self what is the prob of getting a girl which would be 1/4. dont quote me on this until somone says my logic is right but thats how i would do it
i c, if i remb correctly almost all the prob questions had to do with deck of cards. know ur queens and kingsAlmost. Combinations are actually n!/[(n-k)! * k!] and permutations are n!/(n-k)!
Your results actually tells you how many ways three boys can be born out of four children. So, that also tells you how many ways one girl may be born. Still, you have to come up with the total number of ways the parents can have four kids.