Full Member
Apr 7, 2012
Status (Visible)
since Para stabilizes rresonance forms better than Meta, it makes it a more stable anion, therefore more acidic. When you reonate an anion around the benzene ring, neg charge comes to the carbom bearing the EWG, which stabilizes this resonance form. However, when EWG is in the Meta position, negative charge never gets to this carbon and therefore this group does not get a chance to resonance stabilize it. He se, para is more acidic. Hope this helps.


New Member
Oct 27, 2010
Status (Visible)
Drawing resonance structures helps for this stuff. If you draw them, the negative charge will be pushed into the o or p positions & if you consider that there is an electron withdrawing group on there it'll stabilize it. Not sure if that is actually right, but makes sense.
This thread is more than 9 years old.

Your message may be considered spam for the following reasons:

  1. Your new thread title is very short, and likely is unhelpful.
  2. Your reply is very short and likely does not add anything to the thread.
  3. Your reply is very long and likely does not add anything to the thread.
  4. It is very likely that it does not need any further discussion and thus bumping it serves no purpose.
  5. Your message is mostly quotes or spoilers.
  6. Your reply has occurred very quickly after a previous reply and likely does not add anything to the thread.
  7. This thread is locked.