Hmm, this is a weird one. I remember seeing MgX and then placing it in ether. Well all i can think of is I( a very good leaving group) leaving as I- and then the I- will abstract the I+ and make a I2 dihalide and therefore make the Alkene???~^ i think
ethylene (ch2=ch2) is the answer. basically, the Mg reacts with the halide, making it
I ch2 ch2(-)(+)MgI
then, the negative on the carbon creates a double
bond with the other carbon causing the elimination of the I.
ch2=ch2 + I(-)(+)MgI
at least I think that's how the reaction goes. I'm not sure if the final answer has I2 and Mg,ether again, but I do know that ethylene is the major product.
I'm not 100% sure this is how the mechanism is, but i'm pretty sure that this is the gist of it. hope it helps!
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