orgo q..someone?..

[Tina324]

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Which of the following compounds will exhibit the
greatest dipole moment?

A. (Z)-1,2-Dichloro-1,2-diphenylethene
B. (E)-1,2-Dichloro-1,2-diphenylethene
C. 1,2-Dichloro-1,2-diphenylethane
D. 1,2-Dichloroethane
E. 1,2-Difluoroethane

so the answer is A, which i understand..but i was also thikning E could be the answer since F is more electronegative...but then talked myself out of it because it's an alkane..the bonds can rotate..therefore there will never be a fixed dipole moment? am i right?

 

[Tina324]

another one =)



1,3-Cyclopentadiene reacts with sodium metal at low
temperatures and produced the anion version of 1,3-Cyclopentadien with the lone pair between the 2 double bonds (sorry pic wouldn't paste)


A. The reactant is more unstable at reduced
temperatures. B. It exists as a pair of tautomers, of which the enol form predominates.
B. The cation formed is stabilized by aromaticity. C. It is useful as a solvent due to its unusually high
boiling point. C. Sodium metal is highly specific for cycloalkenes.
D. The rehybridization of the saturated carbon atom
provides additional stability to the product. D. It is useful as a solvent due to its polar, protic nature.
E. The anion formed is stabilized by aromaticity.

So, the answer is E which i was gonna choose, but DIDN'T because i rememberd a destroyer q which had a similar compound and the answer key said that the compound wasn't aromatic because the lone pairs resided in a sp3 orbital NOT a p orbital. In this problem isn't the lone pair in a sp3 orbital? so how can this compound be conjugated?

...3 days til D-day😱

 

[IDK]

What was the other question in destroyer?

 

[Sea of ASH]

Which of the following compounds will exhibit the
greatest dipole moment?

A. (Z)-1,2-Dichloro-1,2-diphenylethene
B. (E)-1,2-Dichloro-1,2-diphenylethene
C. 1,2-Dichloro-1,2-diphenylethane
D. 1,2-Dichloroethane
E. 1,2-Difluoroethane

so the answer is A, which i understand..but i was also thikning E could be the answer since F is more electronegative...but then talked myself out of it because it's an alkane..the bonds can rotate..therefore there will never be a fixed dipole moment? am i right?

for e, the fluorines will cancel out the dipole moment... so the molecule is nonpolar