Substitution @ C1 forms an achiral center = 1 Product
Substitution @ C4 forms an achiral center = 1 Product
Substitution @ C2 forms a chiral center (C bonded to Cl, methyl group, 5C group, and H) = 2 Products -- the R and S enantiomer. No matter how you turn the molecules they are not superimposable. In the pictures at the bottom of the solution look at the groups about the chiral carbon and assign priorities. The one on the left is the S enantiomer, the one on the right is the R enantiomer.