The O of the C=O will be protonated by the H+, and then the H20 will attack the C of the C=O. Depending on the nature of the carbonyl's r group(s), it may or may not undergo elimination (by eliminating an r group, or opening up a ring), as the H2O loses one proton, forming a carboxylic acid.
It be easier to help if we had specifics, not just a general case, because different conditions warrant different mechanisms, but generally, the above will happen. Simple addition/elimination.