I don't seem to get the conversion between fisher- projection to a three dimensional structure, because they some how rotate the bonds. Can anyone help me with the KAPLAN final exam Q# 71. why/how do they rotate the bonds?
Help please
I don't seem to get the conversion between fisher- projection to a three dimensional structure, because they some how rotate the bonds. Can anyone help me with the KAPLAN final exam Q# 71. why/how do they rotate the bonds?
Help please
I'm not sure if this is the correct method but it works for this problem. Look at the back carbon and then the front carbon. Make a Newman projection for answer chioce A. So you would have a "Y" with Br on the left, D on the right and OH on the bottom. But turn it so the Br would be on the bottom. To make this, D would be on the left, OH on the right and Br on the bottom.
Next look at the front carbon and do the same. Except the substituents are in an angle so it doesn't look like a normal "Y" but a Y that is turned 60degrees to the right. Anyways, you would have the F on the top right, OH on the bottom right and H on the left. Move it so F would be at OH 's position. After doing this you would have OH on the left, H on right and F on the bottom. And this is the "correct" position for answe A, not the correct answer. So what I just did is align the biggest atom from both carbons and had them pointing downwards on the Newman projections because that location gives the Fischer projection the inward position since it is on the vertical side, while the substiutents on the side are facing upwards.
I hope I didn't confuse you with my long explanations and I'm not sure if this is the correct method as I just noticed that this method gives the right answer when I did it yesterday.
