Orgo question

[Dental2000]

---

Members don't see this ad.

to Reduce Acyl Halides to aldehydes i know we can use H2, Pd/BaSO4 but can LAH also be used for reduction in this case

 

[rockclock]

to Reduce Acyl Halides to aldehydes i know we can use H2, Pd/BaSO4 but can LAH also be used for reduction in this case

LiAlH4 is too strong...you'll reduce all the way to the alcohol.

You need a super-hindered derivative with only one free H: LiAl[OC(CH3)3]3H will stop you at the aldehyde.

 

[Jab1113]

lialh4 is too strong...you'll reduce all the way to the alcohol.

You need a super-hindered derivative with only one free h: lial[oc(ch3)3]3h will stop you at the aldehyde.

+1

 

[invictusx]

Nope, LAH is too strong of a reducing agent to reduce an acyl halide to an aldehyde. Use a mild reducing agent.

 

[LaughingGas]

LiAlH4 is too strong...you'll reduce all the way to the alcohol.

You need a super-hindered derivative with only one free H: LiAl[OC(CH3)3]3H will stop you at the aldehyde.

+2 also called DIBAL 😀

 

[rockclock]

+2 also called DIBAL 😀

Lithium aluminium tri(t-butoxy)hydride and DIBAL are two different compounds...but both should get you the aldehyde.

 

[LaughingGas]

Lithium aluminium tri(t-butoxy)hydride and DIBAL are two different compounds...but both should get you the aldehyde.

you are correct damn it i started forgetting ochem after a month of break 🙁

 

[rockclock]

you are correct damn it i started forgetting ochem after a month of break 🙁

haha don't worry I had to look it up to answer the OP myself.