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How do you find the oxidation number of Cu(NO3)2 ?
Cu(s) + HNO3(aq) --> Cu(NO3)2(aq) + NO(g) + H2O(l)
I forget if you just do Cu=0---> Cu= +2 or something like 2Cu+ 2N+ 6*-2.....N doesn't have a oxidation number of -3 right?
Thankssss
Cu(s) + HNO3(aq) --> Cu(NO3)2(aq) + NO(g) + H2O(l)
I forget if you just do Cu=0---> Cu= +2 or something like 2Cu+ 2N+ 6*-2.....N doesn't have a oxidation number of -3 right?
Thankssss