- Joined
- Dec 12, 2005
- Messages
- 24
- Reaction score
- 0
Hey folks, I have a question regarding centripetal acceleration (v^2/r) and would appreciate it if someone can take a look at the following and let me know if my understanding needs to be corrected. particularly with velocity.
I understand that centripetal force is the force necessary to allow an object to move in a circle with radius r.
In the case of a sattelite orbiting the earth v^2/r must equal the gravitational acceleration in order to avoid falling to earth correct? which means that there is ONLY one particular velocity that will allow the satellite to remain in orbit (v^2/r must equal GMe/r^2). any slower will cause the satellite to fall to earth. any faster and the satellite will exit the orbit, tangential to the orbit.
In the case of a car rounding a curve since the frictional force exerted on the tires is dependent on the velocity of the car, as long at the car's velocity does not exceed the maxiumum frictional force (static friction x Normal Force) the car will stay on the road.
Also, I encountered the following two questions and find the reasoning behind the two answers puzzling.
Q1.
Velocity of satellite is 28000 km/hr at 1600 km above the earth's surface. What is the velocity of at fighter jet 1000km above the earth's surface?
The answer choices given were 17,500 km/hr, 28,000 km/hr, 44,500 km/hr and 56,000 km/hr. The answer choice was 28,000, the reason being that the difference in gravitational acceleration at 1600 km and 1000 km is negligible. Given the answer choices I would have to agree that 28,000 is correct. In reality the fighter jet would have to have a greater velocity than 28000 km/hour correct? Or if one were to assume that gravitational acceleration is negligible velocity would be less for the fighter jet
[(28000km)^2/1600 km] = v^2/1000 km.
Q2.
2 lead sphere's, one placed 1 meter above the other sphere, is dropped at the same time. What will happen to the distance between them as they fall.
a) Remain Constant
b) Distance between the spheres will increase
c) Distance between the speres will decrease
d) cannot recall.
Answer was choice b. I can understand the reasoning behind the answer F=Gm1Me/r^2. But per question 1 if the difference in gravitational acceleration is negligible for two objects at 1600 and 1000 km, wouldn't the difference of g for 2 objects spaced 1 meter apart be even more negligible?
Thanks!
I understand that centripetal force is the force necessary to allow an object to move in a circle with radius r.
In the case of a sattelite orbiting the earth v^2/r must equal the gravitational acceleration in order to avoid falling to earth correct? which means that there is ONLY one particular velocity that will allow the satellite to remain in orbit (v^2/r must equal GMe/r^2). any slower will cause the satellite to fall to earth. any faster and the satellite will exit the orbit, tangential to the orbit.
In the case of a car rounding a curve since the frictional force exerted on the tires is dependent on the velocity of the car, as long at the car's velocity does not exceed the maxiumum frictional force (static friction x Normal Force) the car will stay on the road.
Also, I encountered the following two questions and find the reasoning behind the two answers puzzling.
Q1.
Velocity of satellite is 28000 km/hr at 1600 km above the earth's surface. What is the velocity of at fighter jet 1000km above the earth's surface?
The answer choices given were 17,500 km/hr, 28,000 km/hr, 44,500 km/hr and 56,000 km/hr. The answer choice was 28,000, the reason being that the difference in gravitational acceleration at 1600 km and 1000 km is negligible. Given the answer choices I would have to agree that 28,000 is correct. In reality the fighter jet would have to have a greater velocity than 28000 km/hour correct? Or if one were to assume that gravitational acceleration is negligible velocity would be less for the fighter jet
[(28000km)^2/1600 km] = v^2/1000 km.
Q2.
2 lead sphere's, one placed 1 meter above the other sphere, is dropped at the same time. What will happen to the distance between them as they fall.
a) Remain Constant
b) Distance between the spheres will increase
c) Distance between the speres will decrease
d) cannot recall.
Answer was choice b. I can understand the reasoning behind the answer F=Gm1Me/r^2. But per question 1 if the difference in gravitational acceleration is negligible for two objects at 1600 and 1000 km, wouldn't the difference of g for 2 objects spaced 1 meter apart be even more negligible?
Thanks!