Tricky question depends on how it is worded. Both of you are correct. However i think that i saw that question somewhere and the answer was 6 if i remember correctly.
I would say 6; Nitrogen is sp2 ( so 3 sp2 orbitals.) and one P orbital which participates in the pi system of the ring(the double bond with the next carbon in the ring). The lone pair on nitrogen is in one of its 3 sp2 orbitals and not delocalized into the aromatic pi-system. In acidic solution pyridine is protonated and forms this positively charged cation. ( so bond between nitrogen and H+ is co-ordinate bond)...right?
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