Z zriceman Member 15+ Year Member Joined May 6, 2005 Messages 325 Reaction score 58 Jun 15, 2008 #1 If f(x) = x^(1/2) and g(x) = x^(1/3), what is f(x) * g(x)? can anyone solve this? Dont quite understand the solution in destroyer. Members don't see this ad.
If f(x) = x^(1/2) and g(x) = x^(1/3), what is f(x) * g(x)? can anyone solve this? Dont quite understand the solution in destroyer. Members don't see this ad.
D damon96al New Member 10+ Year Member 15+ Year Member Joined Jun 14, 2008 Messages 7 Reaction score 0 Jun 15, 2008 #2 f(x)=x^1/3 g(x)=x^1/2 therefore f(x)*g(x)=x^(1/2)*x^(1/3)=x^(5/6) when multiplying numbers with the same base and different exponents, add the exponents and keep the base to get the answer. Hope that helps! Upvote 0 Downvote
f(x)=x^1/3 g(x)=x^1/2 therefore f(x)*g(x)=x^(1/2)*x^(1/3)=x^(5/6) when multiplying numbers with the same base and different exponents, add the exponents and keep the base to get the answer. Hope that helps!