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zriceman

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If f(x) = x^(1/2) and g(x) = x^(1/3), what is f(x) * g(x)?

can anyone solve this? Dont quite understand the solution in destroyer.

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f(x)=x^1/3
g(x)=x^1/2
therefore
f(x)*g(x)=x^(1/2)*x^(1/3)=x^(5/6)


when multiplying numbers with the same base and different exponents, add the exponents and keep the base to get the answer. Hope that helps!
 
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