Z zriceman Member 20+ Year Member Jun 15, 2008 #1 Advertisement - Members don't see this ad If f(x) = x^(1/2) and g(x) = x^(1/3), what is f(x) * g(x)? can anyone solve this? Dont quite understand the solution in destroyer.
Advertisement - Members don't see this ad If f(x) = x^(1/2) and g(x) = x^(1/3), what is f(x) * g(x)? can anyone solve this? Dont quite understand the solution in destroyer.
D damon96al New Member 10+ Year Member 15+ Year Member Jun 15, 2008 #2 f(x)=x^1/3 g(x)=x^1/2 therefore f(x)*g(x)=x^(1/2)*x^(1/3)=x^(5/6) when multiplying numbers with the same base and different exponents, add the exponents and keep the base to get the answer. Hope that helps! Upvote 0 Downvote
f(x)=x^1/3 g(x)=x^1/2 therefore f(x)*g(x)=x^(1/2)*x^(1/3)=x^(5/6) when multiplying numbers with the same base and different exponents, add the exponents and keep the base to get the answer. Hope that helps!
