RHONDAROBINSON

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1. Can someone explain these problems to me. Any suggestions on how to study these problems.Thanks in advance.

If a>b>c>d>o, then

(a) ad>bc
(b) ac>b^
(c)abd>abc
(d) a-c>b-d
(e)None of these

2.
x=60(1/45X140);which of the following is equivalent to x?

A. 60(1/90x70
B. 30(1/90X70)
C. 20(1/15X140)
D.20(1/15X140)

3.
If p=3/2,2q=3/p and 5r=2,evaluate pq/(r+p)

4. M+X=1/2(M-x);x/M=?

Rhonda
 

UndergradGuy7

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1. Can someone explain these problems to me. Any suggestions on how to study these problems.Thanks in advance.

If a>b>c>d>o, then

(a) ad>bc
(b) ac>b^
(c)abd>abc
(d) a-c>b-d
(e)None of these

2.
x=60(1/45X140);which of the following is equivalent to x?

A. 60(1/90x70
B. 30(1/90X70)
C. 20(1/15X140)
D.20(1/15X140)

3.
If p=3/2,2q=3/p and 5r=2,evaluate pq/(r+p)

4. M+X=1/2(M-x);x/M=?

Rhonda
For 2 you wrote C and D the same way? The answer is C or D. In x=60(1/45X140) you look at the 60 if they reduce 60 by 1/2, then you have to reduce the 45 by half or the 140. In A they left 60 the same, but multiplied the 45 to make it 90... so thats not right.
B they made 60/2 so 30, but again they made the 45 90 instead of 1/2 22.5

For 1, just try and plug in some numbers and see if it makes sense. for choice b what is it supposed to be b^? I would say the answer is none of them.

For 3, just plug the p q and r into the equation. For q they wrote 2q=3/p, but if you divide by 2 you get 3/2p and if you plug p into it, the numbers cancel and you just get q=p. For r solve for r = 2/5. Then plug everything in. So (3/2 * 3/2) / ( 2/5 + 3/2) = (9/4) / (19/10) = (9/4) * (10/19)

For 4. do you mean M+X=1/(2(M-X)) or 4. M+X=0.5(M-X) ?


Edit: Fixed a mistake on number 3.
 
Last edited:

RHONDAROBINSON

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Sorry for the mistakes. Here are the problem again for 4.


M+X=1/2(M-x);x/m=?


Rhonda
 

TexasOMFS

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For 4. do you mean M+X=1/(2(M-X)) or 4. M+X=0.5(M-X) ?
Pretty sure the OP means the latter. Just tried it both ways and the former gets complicated. Anyways I just worked it with straight up algebra and got x/m=-1/3. Is that correct?
 

dentalWorks

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I'll take a stab at the first one

1. Can someone explain these problems to me. Any suggestions on how to study these problems.Thanks in advance.

If a>b>c>d>o, then

(a) ad>bc
this one cannot be true because it can be EASILY disproven, imagine a=100, b=99, c=98, d=1

(b) ac>b^
umm, whats this "^" supposed to be followed by?

(c)abd>abc
Divide both sides by ab, and you will be left with d>c (obviously incorrect, so this can't be the right answer)

(d) a-c>b-d
this one cannot be true because it can also be easily disproven, imagine a=100, b=99, c=98, d=1
a-c = 2
b-d = 97

(e)None of these
I am not sure if (e) is the correct answer because I still don't know what (b) is