rate law

[joonkimdds]

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intial [A], intial , initial r
1, 1, 1
2, 1, 2
4, 3, 36

the strategy I use is to find the two trials that have the same number to cancel them out.
For example, to find the order of A, i find two B that are the same, 1st and 2nd trial.
when A doubled from 1 to 2, rate also doubled from 1 to 2.
That means the order of A is 1

but now I am having trouble finding the order of B because there are no trials that have the same two [A] to cancel out.

how do I solve this?

 

[Sea of ASH]

ok now that u got the order of A ur half way there...

use rxn3/rx2:

36/2 = (4/2)^1 (3/1)^X
18 = 2 (3)^X
9 = (3)^X

X=2, second order.... overall 3rd order rxn

 

[joonkimdds]

ok now that u got the order of A ur half way there...

use rxn3/rx2:

36/2 = (4/2)^1 (3/1)^X
18 = 2 (3)^X
9 = (3)^X

X=2, second order.... overall 3rd order rxn

Since rate = k[A]^x^y, using what you used mean that we are ignoring k, isn't it?

 

[Sea of ASH]

ya cuz we are dividing the two rxn's so the k cancels out ....

 

[joonkimdds]

ahhhh~~~~~
Ohh~~~~~~~~~~!!!!!!!
right right~!!!! 🙂
btw, ur avatar scares me, LOL.

 

[Sea of ASH]

lol y? its just my baby pic hahaha

poor thing is sooooo stressed out and depressed hahaha so i kinda thought thats me while i finish up with DAT's