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Started by n2o*
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The first thing I would do is realize that their is 6 gallons of pulp to start with as 20% of 30 is 6. Then set up this formula 6+x=(30+x)/2 and solve. X=amount of pulp you need to add to get a 50% mixture. Solving this formula I got 18 gallons are needed to make a 50% mixture.
jumdent said:The first thing I would do is realize that their is 6 gallons of pulp to start with as 20% of 30 is 6. Then set up this formula 6+x=(30+x)/2 and solve. X=amount of pulp you need to add to get a 50% mixture. Solving this formula I got 18 gallons are needed to make a 50% mixture.
50% =18gallons
How, total is 36gallons with the 20% plup. 50% of that will be 18 gallons.
jumdent said:The first thing I would do is realize that their is 6 gallons of pulp to start with as 20% of 30 is 6. Then set up this formula 6+x=(30+x)/2 and solve. X=amount of pulp you need to add to get a 50% mixture. Solving this formula I got 18 gallons are needed to make a 50% mixture.
thanx a lot. The ans is 18.
Here is another one:
A car travels 10 mi at an average speed of 40mph. What must the average speed be, in mph, during the next 10 mi for the total average speed to be 30mph?
The ans. is 24. Explanations pls 🙂
n2o* said:thanx a lot. The ans is 18.
Here is another one:
A car travels 10 mi at an average speed of 40mph. What must the average speed be, in mph, during the next 10 mi for the total average speed to be 30mph?
The ans. is 24. Explanations pls 🙂
WOW that was a tough one!!!! but i got it Damn MPH keeps throwing me off.
First lets define X as the miles you need to travel in 1 hour for the next 10miles to reach the average 30MPH.
40 MPH = (1 hour/40 miles)
10 miles (1 hour/40 miles) + 10 miles (1 hour/ X ) = 20 miles (1 hour/30 miles)
x = 24 MPH.
n2o* said:thanx a lot. The ans is 18.
Here is another one:
A car travels 10 mi at an average speed of 40mph. What must the average speed be, in mph, during the next 10 mi for the total average speed to be 30mph?
The ans. is 24. Explanations pls 🙂
Yah this one threw me too....I did a bit different.
Use the formula [Time=distance/rate]. Find the time first 10miles/40mph = 1/4hour,
next find the total time [20miles/30mph=2/3hr] substract 2/3hr-1/4hr = 5/12hr,
now you can find the rate for the second 10miles. [rate=distance/time]=[10miles / 5/12hr =
24mph]
Maxmuscle27 said:Yah this one threw me too....I did a bit different.
Use the formula [Time=distance/rate]. Find the time first 10miles/40mph = 1/4hour,
next find the total time [20miles/30mph=2/3hr] substract 2/3hr-1/4hr = 5/12hr,
now you can find the rate for the second 10miles. [rate=distance/time]=[10miles / 5/12hr =
24mph]
hmmm... good. good. thanks a lot.
Maxmuscle27 said:Yah this one threw me too....I did a bit different.
Use the formula [Time=distance/rate]. Find the time first 10miles/40mph = 1/4hour,
next find the total time [20miles/30mph=2/3hr] substract 2/3hr-1/4hr = 5/12hr,
now you can find the rate for the second 10miles. [rate=distance/time]=[10miles / 5/12hr =
24mph]
or you could do it the stupid way which is. Take the average speed of 30 times by 2 get 60.
So now we have 60 subtract 40 you get 20 close enough to 24.
newbe said:or you could do it the stupid way which is. Take the average speed of 30 times by 2 get 60.
So now we have 60 subtract 40 you get 20 close enough to 24.
nope, this was a multiple choice question with 20 as one of the options. u would have gotten it incorrect.
n2o* said:nope, this was a multiple choice question with 20 as one of the options. u would have gotten it incorrect.
interesting I did not get to that one yet in topscore. This means I will have to do it the hard way. Thanks.
