Square/Cube roots and Scientific Notation

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.
Get help with your application

Use all the free resources available to you from SDN: articles, guides, expert advising, forums discussions, and school research.

mitchlucker

Full Member
10+ Year Member
Advertisement - Members don't see this ad
Hi, saw a thread 7 years ago for this but it didn't help me out much.

Can anyone tell me an easy way to estimate large/very small square and cube roots?

I get tripped up on problems like solubility when solving for X and I have things like 4.4x10^-14 = 4X^3.
 
Hi, saw a thread 7 years ago for this but it didn't help me out much.

Can anyone tell me an easy way to estimate large/very small square and cube roots?

I get tripped up on problems like solubility when solving for X and I have things like 4.4x10^-14 = 4X^3.

4.4 * 10^-14 = 4 * x^3
1.1 * 10^-14 = x^3

That's approximately the same as:
10^-14 = x^3

Now, you know that (10^-5)^3 = 10^-15 and (10^-4)^3 = 10^-12. 10^-14 is closer to the former, so you know that x is closer to 10^-5 than 10^-4. 10^-15 is an order of magnitude away from 10^-14, so you want the cube root of 10^1, which is between 2 and 3 (but definitely much closer to 2; I'd estimate around 2.2 or 2.3).
Putting that all together, you get x as about 2.2 * 10^-5.

Does that help? It's kind of complicated, but as you get better, a lot of this stuff becomes quite intuitive.