D Dencology Full Member 10+ Year Member 15+ Year Member Joined Mar 7, 2008 Messages 396 Reaction score 0 Points 0 Pre-Dental Oct 29, 2008 #1 Advertisement - Members don't see this ad what volume of HCl was added to 20 mL of 1M NaOH is titrated with 1M HCl to produce a pH=2? i just don't get this problem. ans. is 20.4mL
Advertisement - Members don't see this ad what volume of HCl was added to 20 mL of 1M NaOH is titrated with 1M HCl to produce a pH=2? i just don't get this problem. ans. is 20.4mL
doc toothache Full Member 15+ Year Member Joined Jan 17, 2006 Messages 8,521 Reaction score 2,797 Points 5,461 Dentist Oct 29, 2008 #2 http://forums.studentdoctor.net/showthread.php?t=574267 Upvote 0 Downvote
D Dencology Full Member 10+ Year Member 15+ Year Member Joined Mar 7, 2008 Messages 396 Reaction score 0 Points 0 Pre-Dental Oct 29, 2008 #3 hey, there are some confusing statements out there. if you don't mind, can you let me know how they got 0.01 and then 20.04? Upvote 0 Downvote
hey, there are some confusing statements out there. if you don't mind, can you let me know how they got 0.01 and then 20.04?
doc toothache Full Member 15+ Year Member Joined Jan 17, 2006 Messages 8,521 Reaction score 2,797 Points 5,461 Dentist Oct 29, 2008 #4 Dencology said: what volume of HCl was added to 20 mL of 1M NaOH is titrated with 1M HCl to produce a pH=2? i just don't get this problem. ans. is 20.4mL Click to expand... It takes 20 ml of 1M NaOH to neutralize 20 ml of HCl for a total volume of 40 ml of solution (pH 7). The question then becomes what volume of 1 M HCl is needed to obtain 40 ml of 0.01M solution. M1V1=M2V2 (1)V1= (0.01)(40) V1= 0.4 Total volume = 20 + 0.4 = 20.4 Last edited: Oct 30, 2008 Upvote 0 Downvote
Dencology said: what volume of HCl was added to 20 mL of 1M NaOH is titrated with 1M HCl to produce a pH=2? i just don't get this problem. ans. is 20.4mL Click to expand... It takes 20 ml of 1M NaOH to neutralize 20 ml of HCl for a total volume of 40 ml of solution (pH 7). The question then becomes what volume of 1 M HCl is needed to obtain 40 ml of 0.01M solution. M1V1=M2V2 (1)V1= (0.01)(40) V1= 0.4 Total volume = 20 + 0.4 = 20.4