There is a rotating cylinder ride at an amusement park so that when the ride achieves a speed of v, the floor can drop leaving the person suspended. The radius is 4m, coefficient of static friction is 0.5. What is the tangential speed required to suspend a 50 kg man?
Answer: 9m/s
To answer this problem (or problems similar to this), must I always assume that the normal force equals the centripetal force? And why does the normal force equal the centripetal force if the normal force is by definition opposite the gravitational force?? That connection didn't come to me right away and took me like 10 min to answer...
[Fn = Fc = (mv^2)/r. And to make the man suspend, the Ff = Fg. Since Ff = mu(s)*Fn, plug in and you get mg = mu(s)*(mv^2)/r. ]
Answer: 9m/s
To answer this problem (or problems similar to this), must I always assume that the normal force equals the centripetal force? And why does the normal force equal the centripetal force if the normal force is by definition opposite the gravitational force?? That connection didn't come to me right away and took me like 10 min to answer...
[Fn = Fc = (mv^2)/r. And to make the man suspend, the Ff = Fg. Since Ff = mu(s)*Fn, plug in and you get mg = mu(s)*(mv^2)/r. ]