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This problem comes from kaplan book pg 108.
If x is an acute angle for which tan^2(x) = 6tan(x) - 9, what is the measure of x?
So this is the quadratic equation and it comes ot to be tanx = 3.
x = arctan(3) and the answer comes out to approximately 71.6. How am I suppose to possibly know what the inverse tan is suppose to be to solve this?
If x is an acute angle for which tan^2(x) = 6tan(x) - 9, what is the measure of x?
So this is the quadratic equation and it comes ot to be tanx = 3.
x = arctan(3) and the answer comes out to approximately 71.6. How am I suppose to possibly know what the inverse tan is suppose to be to solve this?
