- Joined
- Mar 11, 2017
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- 21
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Just watched Chad's video where he explains that high activation energy equates to a low rate constant. I don't understand why. Can someone explain?
Thank you.
Soooooo, the bigger the hill is (activation energy), the slower the reaction is to complete?
Thank you.
Soooooo, the bigger the hill is (activation energy), the slower the reaction is to complete?
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