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1H NMR spectrum
Started by nhasifuture
I'm gonna try my best to expalin this. Look at the attached picture of m-xylene and give each carbon on the ring a number. Start from the carbon on the top that has a methyl attached which would be carbon #1 then go clockwise...Anyways, both CH3's show a singlet and the hydrogen on carbon #2 shows a singlet also. Carbon #4 and #6 both show doublet and carbon #5 shows a triplet...Hope it makes sense!
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thanks, but i still dont see how carbon#6 shows a doublet and there is only 1 doublet on the answer. I thought C#6 would show a singlet.
oops, never mind I think i got it! Thanks again for a quick response.
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There is one Hydrogen on the carbon next to the 6 position. If its neighboring carbons have one H then n+1 is 2, two peaks or a doublet.
I'm gonna try my best to expalin this. Look at the attached picture of m-xylene and give each carbon on the ring a number. Start from the carbon on the top that has a methyl attached which would be carbon #1 then go clockwise...Anyways, both CH3's show a singlet and the hydrogen on carbon #2 shows a singlet also. Carbon #4 and #6 both show doublet and carbon #5 shows a triplet...Hope it makes sense!
What about Carbon # 3, I would expect it to be a sextet...or am I wrong.....??
Carbon #3 doesn't have any hydrogens!
oh...So N+1 applies only when there is at least a single Hydrogen present...not otherwise..!!
That clears it up for ......Thanks......!!
I would be really looking for carbon 1 and 3 in NMR, if you hadn't enlightened me...lol...Thanks again..!!
oh...So N+1 applies only when there is at least a single Hydrogen present...not otherwise..!!
That clears it up for ......Thanks......!!
I would be really looking for carbon 1 and 3 in NMR, if you hadn't enlightened me...lol...Thanks again..!!
Yeah make sure you look for Carbon 1 and 3 in 13C NMR but not 1H NMR 😀
Yeah make sure you look for Carbon 1 and 3 in 13C NMR but not 1H NMR 😀
Do we need to know 13C NMR for DATs....??
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Do we need to know 13C NMR for DATs....??
Indeed
To find peak character, use the formula n+1 where n=number of adjacent H's
RED H's: Split by 0 h's on adjacent carbon (0+1=1 Singlet)
GREEN H: Split by 0 h's on adjacent carbon (0+1=1 Singlet)
BLUE H's: Split by 1 adjacent grey H (1+1=2 doublet)
GREY H: Split by 2 adjacent blue H (2+1=3 triplet)
RED H's: Split by 0 h's on adjacent carbon -doublet
GREEN H: Split by 0 h's on adjacent carbon -sept ( 7)
BLUE H's: Split by 1 adjacent grey H (1+1=2 doublet)
GREY H: Split by 2 adjacent blue H (2+1=3 triplet
Which part i missed?
GREEN H: Split by 0 h's on adjacent carbon -sept ( 7)
BLUE H's: Split by 1 adjacent grey H (1+1=2 doublet)
GREY H: Split by 2 adjacent blue H (2+1=3 triplet
Which part i missed?
RED H's: Split by 0 h's on adjacent carbon -doublet
GREEN H: Split by 0 h's on adjacent carbon -sept ( 7)
BLUE H's: Split by 1 adjacent grey H (1+1=2 doublet)
GREY H: Split by 2 adjacent blue H (2+1=3 triplet
Which part i missed?
For the red one: there are no hydrogens on the adjacent carbon atoms so you only get a singlet!
For the green one: same thing as the red one! there are no hydrogens on number 1 and 3 carbons!
Which singlet peak would be more downfield, the red one or green?
The green by a drop i think.
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