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can someone please explain why the 1H NMR spectrum of m-xylene shows 4 peaks: 2s singlets, 1 doublet, and 1 triplet. Thanks!
I'm gonna try my best to expalin this. Look at the attached picture of m-xylene and give each carbon on the ring a number. Start from the carbon on the top that has a methyl attached which would be carbon #1 then go clockwise...Anyways, both CH3's show a singlet and the hydrogen on carbon #2 shows a singlet also. Carbon #4 and #6 both show doublet and carbon #5 shows a triplet...Hope it makes sense!
Carbon #3 doesn't have any hydrogens!
oh...So N+1 applies only when there is at least a single Hydrogen present...not otherwise..!!
That clears it up for ......Thanks......!!
I would be really looking for carbon 1 and 3 in NMR, if you hadn't enlightened me...lol...Thanks again..!!
Yeah make sure you look for Carbon 1 and 3 in 13C NMR but not 1H NMR 😀
Do we need to know 13C NMR for DATs....??
RED H's: Split by 0 h's on adjacent carbon -doublet
GREEN H: Split by 0 h's on adjacent carbon -sept ( 7)
BLUE H's: Split by 1 adjacent grey H (1+1=2 doublet)
GREY H: Split by 2 adjacent blue H (2+1=3 triplet
Which part i missed?
Which singlet peak would be more downfield, the red one or green?