F fdat94 Full Member 7+ Year Member Joined Apr 22, 2016 Messages 101 Reaction score 12 May 6, 2016 #1 Members don't see this ad. Can someone please explain this, I'm getting so frustrated
DAT Destroyer Dr. Romano and Nancy Lifetime Donor Verified Member Vendor 20+ Year Member Gold Donor Joined Mar 12, 2005 Messages 5,472 Reaction score 3,519 May 6, 2016 #2 fdat94 said: Can someone please explain this, I'm getting so frustrated Click to expand... Here are errors that are on the 2009 DAT, not sure but this might help! Can you post the question. http://forums.studentdoctor.net/threads/2009-dat-sample-test-errors-confirmed-by-ada.828825/ Upvote 0 Downvote
fdat94 said: Can someone please explain this, I'm getting so frustrated Click to expand... Here are errors that are on the 2009 DAT, not sure but this might help! Can you post the question. http://forums.studentdoctor.net/threads/2009-dat-sample-test-errors-confirmed-by-ada.828825/
F fdat94 Full Member 7+ Year Member Joined Apr 22, 2016 Messages 101 Reaction score 12 May 6, 2016 #3 orgoman22 said: Here are errors that are on the 2009 DAT, not sure but this might help! Can you post the question. http://forums.studentdoctor.net/threads/2009-dat-sample-test-errors-confirmed-by-ada.828825/ Click to expand... Its not on there, heres the question: Attachments Screen Shot 2016-05-06 at 3.23.25 PM.png 270.8 KB · Views: 181 Upvote 0 Downvote
orgoman22 said: Here are errors that are on the 2009 DAT, not sure but this might help! Can you post the question. http://forums.studentdoctor.net/threads/2009-dat-sample-test-errors-confirmed-by-ada.828825/ Click to expand... Its not on there, heres the question:
F fdat94 Full Member 7+ Year Member Joined Apr 22, 2016 Messages 101 Reaction score 12 May 6, 2016 #4 fdat94 said: Its not on there, heres the question: Click to expand... Correct answer is B Upvote 0 Downvote
F fdat94 Full Member 7+ Year Member Joined Apr 22, 2016 Messages 101 Reaction score 12 May 6, 2016 #6 jjj7236 said: find mol of NaoH, which will be .05 mol. Now this will be same # mol as the acid (since its a neutralization rxn). now just plug these into M = mol/V which would be .05 mol Acid / .1 L. and this is .5 M (answer B) Click to expand... Sorry, where are you getting .1 L from? This is what I'm getting to.. .05 moles of acid, M=moles/L M=.05/.05 M=1 Upvote 0 Downvote
jjj7236 said: find mol of NaoH, which will be .05 mol. Now this will be same # mol as the acid (since its a neutralization rxn). now just plug these into M = mol/V which would be .05 mol Acid / .1 L. and this is .5 M (answer B) Click to expand... Sorry, where are you getting .1 L from? This is what I'm getting to.. .05 moles of acid, M=moles/L M=.05/.05 M=1
D dentalstudent2021 May 6, 2016 #7 my bad. here you go http://forums.studentdoctor.net/threads/gc-question.718053/ Upvote 0 Downvote