#44 2009 ADA DAT test

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find mol of NaoH, which will be .05 mol. Now this will be same # mol as the acid (since its a neutralization rxn). now just plug these into M = mol/V which would be .05 mol Acid / .1 L. and this is .5 M (answer B)
Sorry, where are you getting .1 L from?

This is what I'm getting to..
.05 moles of acid,
M=moles/L
M=.05/.05
M=1