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Can we start an official aamc cbt11 thread. I took this test a few days ago and have some questions. Can I just start this thread? Or, is that sort of behavior for the more senior members.
I picked D, "opposition, because the author would believe that such a policy should not be based on a quota system" because of the passage sentence:
"First, academia has to overcome its prejudice against the local and the provincial, so that its hiring committees do not include non-native status as an implicit qualification for employment."
Does that sentence not oppose the use of quotas?![]()
Can someone explain PS #6 to me? I thought when temperature goes up, resistivity goes up. Wouldn't proton conductivity decrease with increasing temperatures?
Sos!
PS #11
Why is dG negative? It says that the reaction decomposes when heated. Would this not mean it doesn't decompose at room temperature?
also
BS#148
Alveolar walls are only composed of a single cell layer as opposed to single cell with underlying connective tissue. From anatomy class I know alveolar walls also have a basement membrane on them separating them from the blood vessels. Is that answer wrong because the connective tissue is 'overlying'?
PS #21
Which of the following properties of a wave is independent of all others?
The answer was amplitude
but isn't frequency supposed to be an independent property of a wave?
#46
Which of the following best explains what happens at the molecular level to the supporting pillars as the water level in the storage tank rises?
I wasn't sure can someone explain why it's C?
Verbal
#74
Which subject would be most useful for an economics professor to know
#87
The authors imply that the portuguese ambassador applauded the french national assembly because of genuine sympathy for their ideals. Alternatively, the abassador's action could be explained as indicating that?
I guess A makes sense but I'm not sure where they are getting it from, also what about choice C?
BS
#110
Ebola passage
131, 135, 136
Q100 in BS. This seems like it should've been easier, but I guess I overthought it. I picked C, because since LH controls estrogen secretion, and the table shows that when you have a the NPY alone you get less LH (albeit only a little), then I figured you'd get less estrogen. Now I know the reason it's A is because "there's no change", but my question is how exactly do I distinguish this? Yes, obviously the values are close, but the values with NPY alone are still lower than the control even though they're close. I figured since it wasn't like +/- 0.01 then it had it least some effect. This felt like one of those verbal questions where seemingly equally strong arguments for both choices could be given.
Can someone give some insight beyond just saying that the values are close so it had no effect?
For #106 in BS
Are we seriously supposed to know which peptidases are made/located in which GI compartment?
I think you were talking about that question where the answer was trypsin
Trypsin is produced by the pancreas
The stomach enzyme is pepsin not trypsin
Also the other choices were what the stomach does
Can anyone explain the reasoning on 136? I got the question correct, but now I realize my reasoning was fallacious and I don't understand that of the explanation.
The stem says a nucleotide was added to the ORF. Okay, fine. The explanation says we should expect a different amino acid at the C-terminus of the translated polypeptide. Why? We're not told where the nucleotide was added into the ORF (it could have been inserted anywhere, not necessarily added to the end), and even if it were added to the end, we wouldn't necessarily get a changed amino acid at the end of the polypeptide.
Furthermore how is it even possible to add in a single nucleotide and not create or eliminate a stop codon?
If the sGP mRNA sequence is this:
AUG|GCU|AUA|CUA|UGA
And we add a single nuc. in the ORF (before the stop codon), we get:
AUG|GCU|AUA|CUA|UUG|A
Which eliminates our stop codon because it shifts the reading frame.
I'm confused.
Can anyone explain the reasoning on 136? I got the question correct, but now I realize my reasoning was fallacious and I don't understand that of the explanation.
The stem says a nucleotide was added to the ORF. Okay, fine. The explanation says we should expect a different amino acid at the C-terminus of the translated polypeptide. Why? We're not told where the nucleotide was added into the ORF (it could have been inserted anywhere, not necessarily added to the end), and even if it were added to the end, we wouldn't necessarily get a changed amino acid at the end of the polypeptide.
Furthermore how is it even possible to add in a single nucleotide and not create or eliminate a stop codon?
If the sGP mRNA sequence is this:
AUG|GCU|AUA|CUA|UGA
And we add a single nuc. in the ORF (before the stop codon), we get:
AUG|GCU|AUA|CUA|UUG|A
Which eliminates our stop codon because it shifts the reading frame.
I'm confused.
The open reading frame is the portion of the RNA that doesn't have stop codons. So, if you add a nucleotide there, then you'll likely prolong translation and produce a peptide chain of longer length. As such, you'll likely have a different carboxy terminus.
Also, I think you have to assume it's added at the end since it does not change any stop codons
No, you won't. Adding one nucleotide cannot add a single amino acid. The polypeptide length remains the same.
If it's added at the end of the ORF if still changes the stop codon.
Write out a sequence and see.
well, if you add a nucleotide to the end of the ORF (before the stop codon) then you change the reading frame at the very end. The stop codon is then likely no longer a stop codon.. and you add more amino acids
No, you won't.
Write out a sequence and see.
Question stem says no stop codon is eliminated.
Question stem says no stop codon is eliminated.
I think I might be terribly confused about this question due to the weird way the answer explanation is written...
PS, #20.
The compressive strength of a human bone is about 2 x 10^8 N/m^2. What crushing mass, supported by an upright forearm, would cause a 1% change in length of a 5 cm^2 cross sectional area of forearm bone?
The answer explanation says that the formula given in the passage is rearranged to..
"F = (delta L/L) x E x A. Solving for m gives 0.01 x 5 x 10^-4 m^2 x 2 x 10^8 N/m^2 = 100 kg or 10^2 kg"
First of all, whoa AAMC. How about some parentheses in there so it's not super hard to tell which terms are which. Second of all, I'm assuming that the "5 x 10^-4 m^2" term is from the cross sectional area... But why is it to the -4? Shouldn't it be 5 x 10^-2?? I just feel like I'm missing something but I can't for the life of me figure it out.
Thanks guys 🙂
When going from units of cm^2 to m^2 it is a reduction of (10^-2)^2 which leads to 10^-4. If the conversion was from km^2 to m^2 you multiply the number by (10^3)^2 or 10^6. I made the same mistake as you.
For #25, I think one way to look at it is to, as you say, notice that air resistance is proportional to v^2, so velocity contributes more to the force of air resistance than surface area does.
I have a question on #23:
The optical power P of a lens is expressed in diopters: P = 1/f, where f is the focal length in meters. Given that the lens-to-retina distance in the human eye averages 2.0 cm, which of the following is closest to the power of the lens of the human eye?
A. 0.05
B. 2
C. 10
D. 40
The correct answer is D (weird, because 1/(2.0 * 10^-2) is really 50, but 40 is the "closest"). How were you supposed to know that the lens-to-retina distance is the focal length as opposed to the radius of curvature? If you were to assume 2.0 cm was the radius of curvature, focal length would be 1 cm, and P would be 100 which isn't an answer, so I didn't have to worry about it for this question, but I am still curious as to what would have led one to determine that "lens-to-retina distance" = f. Thanks!