For #25, I think one way to look at it is to, as you say, notice that air resistance is proportional to v^2, so velocity contributes more to the force of air resistance than surface area does.
I have a question on #23:
The optical power P of a lens is expressed in diopters: P = 1/f, where f is the focal length in meters. Given that the lens-to-retina distance in the human eye averages 2.0 cm, which of the following is closest to the power of the lens of the human eye?
A. 0.05
B. 2
C. 10
D. 40
The correct answer is D (weird, because 1/(2.0 * 10^-2) is really 50, but 40 is the "closest"). How were you supposed to know that the lens-to-retina distance is the focal length as opposed to the radius of curvature? If you were to assume 2.0 cm was the radius of curvature, focal length would be 1 cm, and P would be 100 which isn't an answer, so I didn't have to worry about it for this question, but I am still curious as to what would have led one to determine that "lens-to-retina distance" = f. Thanks!