The answer to your first question is D. Due to the common ion effect, and since Fluorine would be in the largest quantity when aqueous, a solution with the highest concentration of F- ion would shift the reaction to the left, decreasing the solubility.
The answer to your second question would be B. While choice D is tempting, when placed in water it would produce a strong base and a strong acid - resulting in a neutral solution. In B however, we would produce a strong base (NaOH) and a weak acid - resulting in an overall basic solution.
Hope this is helpful.