form an epoxide by MCPBA with an alkene and then use H30+ to break it and it will form a trans diol
only way i know that will form a trans diol
and the cis ones u mention
KMNO4 cold, dilute + alkene-> cis diol (make sure its dilute and cold otherwise it will continue reacting and cleaving it into ketone and Carboxy acid)
1)OSO4/ 2)H202 +alkene -> cis diol
Keep in mind if you create an oxirane and then attack it with acid and water, the attack can occur at either side of the ring, creating a pair of enantiomers. If you want sterochemical specificity, go with KMnO4. 🙂
I understand your reasoning behind that, planar molecule, equal probability of attack from both sides, however epoxides are known to react with acid catalysts to form diols (glycols) via anti-addition. So no enantiomers here.
Keep in mind if you create an oxirane and then attack it with acid and water, the attack can occur at either side of the ring, creating a pair of enantiomers. If you want sterochemical specificity, go with KMnO4. 🙂
I thought an acid would attack an oxirane at the most substituted carbon, while a base attacks the least substituted. So if you're using either an acid OR a base, you wouldn't get mixed products.
I thought an acid would attack an oxirane at the most substituted carbon, while a base attacks the least substituted. So if you're using either an acid OR a base, you wouldn't get mixed products.