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Major Problem

Discussion in 'DAT Discussions' started by DMD2BE1122, Jul 25, 2006.

  1. DMD2BE1122

    2+ Year Member

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    Whats Up.

    Listen I already took the DAT before and when I did take it I completely bombed the G chem section. I started studying again and have been through the kaplan book twice and I AM STILL STRUGGLING WITH IT. Limiting Reagents and Acid base is killing. Stochemotry is also killing me. Any adive cause the more problems I do is just making me more mad cause I CANT GET THESE PROBLEMS RIGHT. I took top score g chem test and got a 15 on it. Its not normal. How can i get a 21 on the ochem section but bomb the gchem section.
     
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  3. jackbauer!

    jackbauer! Guest

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    if you're having troubles still, then whip out the textbook or consult a graduate ta at your school. the topics you're struggling with are among the easiest in gchem and can be easily cleared up with practice.

    jb!
     
  4. Arsenalista

    Arsenalista Member
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    use a general chemistry textbook - it's the best resource you can possibly have. and then practice, practice, practice. :thumbup:
     
  5. grapeflavorsoda

    grapeflavorsoda Senior Member
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    buy EK 1001 gchem book for mcat.

    it is all passage-independent, and it is meant to boost your understanding of gchem material itself.

    textbook is always a good option.
     
  6. dontbam

    dontbam Member
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    just give up because if you can't do gchem then you don't belong in dental school and you don't deserve to have passed your freshman chem classes...haha no just kidding :)

    yeah like the guy above, exam krackers is pretty good for GChem, i recommend it too
     
  7. dental#1

    dental#1 Fla DDS
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    If you are haveing trouble there is a program called Chem Skill builder. It is great! I'll give you a quick example of the limiting rxn:

    a) 3 moles of C2H2 were ALLOWED to react with 10 moles of O2:

    2C2H2 + 5O2 --> 4CO2 + 2H20

    What is the limiting reagent?

    NEED Available

    C2H2/O2= 2mol/5mol=.4 C2H2/O2=3mol/10mol=.3

    Since you need .4C2H2 and only have .3C2H2 C2H2 that is your limiting reagent. If you invert the reactants you will see that you have more O2 than you need!

    Now it may ask you for a theoretical yield of CO2 if it does use the limiting reagent C2H2 available to start:

    (3molC2H2)(4molCO2/2molC2H2)(MWCO2)=theo in (g)

    then you can take that # to get the % yield if asked.
    For exp: The problem would say the actual yield was only 2.5g

    Actual/Theo*100%= %yield

    Hope this helps!
     
  8. dental#1

    dental#1 Fla DDS
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