Q: molarity of K2SO4 in aq. solution created by adding 112g of KOH(solid) to 500mL of 0.5M H2SO4(aq)
the answer is 0.5M but I don't know why....
-mole of KOH in 500mL = 112g x 1/56g x 1/.5 = 4M and?
could anyone can help me out?
the answer is 0.5M but I don't know why....
-mole of KOH in 500mL = 112g x 1/56g x 1/.5 = 4M and?
could anyone can help me out?