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Here is a link the problem: (Problem # 10.4)
http://jpkc.zju.edu.cn/k/146/Organic_Chemistry_Level_1/Answer_for_mcmurry/Chapter10.pdf
I understand how to get the four different products. I cannot figure out how they got the percentages. Here is what I know, maybe someone can fill in a missing link.
Here are the four products:
1-chloro-2-methylbutane
1-chloro-3-methylbutane
2-chloro-2-methylbutane
2-chloro-3methylbutane
How do I find the approximate %'s of each product? 2-methylbutane has 9 primary hydrogens, 1 secondary hydrogen and 1 tertiary hydrogen. But I don't understand how to work this out following my book example (it's mcmurry 8th ed). In the book they give the ratio's of the two products formed from chlorination of butane, (30:70) and chlorination of 2-methylpropane (35:65) as examples. It says to take the number of primary hydrocarbons and divide it by the ratio. My question is how do I get this ratios if they are not provided? Any help would be great, thanks.
http://jpkc.zju.edu.cn/k/146/Organic_Chemistry_Level_1/Answer_for_mcmurry/Chapter10.pdf
I understand how to get the four different products. I cannot figure out how they got the percentages. Here is what I know, maybe someone can fill in a missing link.
Here are the four products:
1-chloro-2-methylbutane
1-chloro-3-methylbutane
2-chloro-2-methylbutane
2-chloro-3methylbutane
How do I find the approximate %'s of each product? 2-methylbutane has 9 primary hydrogens, 1 secondary hydrogen and 1 tertiary hydrogen. But I don't understand how to work this out following my book example (it's mcmurry 8th ed). In the book they give the ratio's of the two products formed from chlorination of butane, (30:70) and chlorination of 2-methylpropane (35:65) as examples. It says to take the number of primary hydrocarbons and divide it by the ratio. My question is how do I get this ratios if they are not provided? Any help would be great, thanks.