Need a better understanding of a Dr. Collin's Chem Question

[MegaRave214]

N2(g) + 3H2(g) <--> 2NH3(g)

If the volume of the container in which the above equilibrium had been established were to be halved, then when equilibrium were reestablished the

-Moles of N2 would be increased
-Moles of NH3 would be increased (ANSWER)
-Moles of NH3 would be decreased
-Moles of NH3 would remain the same


Thank you

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[deleted727644]

When volume is halved, the pressure increases by a factor of 2 because they're inversely proportional to each other. So, when the pressure increases, equilibrium would get shifted to side with the less moles of gas. In this case it's NH3 (2 moles) vs the left side (4 moles)

 

[Bareitashvilli]

N2(g) + 3H2(g) <--> 2NH3(g)

If the volume of the container in which the above equilibrium had been established were to be halved, then when equilibrium were reestablished the

-Moles of N2 would be increased
-Moles of NH3 would be increased (ANSWER)
-Moles of NH3 would be decreased
-Moles of NH3 would remain the same


Thank you

Exactly what the person above me said.