What is the maximum concentration of fluoride ions that could be present in 0.032M Ba(NO3)2 (Ksp,BaF2 = 3.2x10-8)?
A) 1.0x10-3M
B) 2.0x10-3M
C) 5.0x10-4M
D) 1.0x10-6M
BaF2(s) → Ba2+(aq) + 2F-(aq) Ksp = [Ba2+][F-]^2
3.2x10-8 = (0.032)[F-]^2 and so 3.2×10^−8/0.032=[F-]^2
3.2×10−2/3.2×10−8 =[F−]2
(1.0×10−6)^1/2 =[F−] and so [F−]=1.0×10−3M
I do not understand why we are assuming that [F-]=[x]^2 and not [2x]^2??
A) 1.0x10-3M
B) 2.0x10-3M
C) 5.0x10-4M
D) 1.0x10-6M
BaF2(s) → Ba2+(aq) + 2F-(aq) Ksp = [Ba2+][F-]^2
3.2x10-8 = (0.032)[F-]^2 and so 3.2×10^−8/0.032=[F-]^2
3.2×10−2/3.2×10−8 =[F−]2
(1.0×10−6)^1/2 =[F−] and so [F−]=1.0×10−3M
I do not understand why we are assuming that [F-]=[x]^2 and not [2x]^2??