- Joined
- Jun 1, 2017

- Messages
- 61

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- 12

Researchers collected the following data for an enzyme-catalyzed reaction.

[Substrate] (muM)

3

6

10

20

50

100

1000

10,000

Vo (muM/min)

22

53

100

129

162

180

199

200

What is the approximate numerical value of the slope of the Lineweaver-Burk plot of these kinetic data?

Choices:

A) 0.01

B)0.05

C)10

D) 50

The answer is B- 0.05, and this was done by doing 10/200 using the slope equation m=Km/Vmax.

I understand how the Vmax is 200, because once the concentration of substrate is saturated, the max velocity shows that it would be 200. I don't understand why 10 is the Km and how to know that it is 10?

Thanks in advance.