- Joined
- Jul 6, 2006
- Messages
- 121
- Reaction score
- 1
1) Do animal cells have vacuoles? Ive found a good 30 contradicting answers.
2) Do plant cells have centrioles? I thought no...
3) During competitive inhibition, the inhibitor can bind to the substrate site, OR the allosteric site, correct? With non-comp- its just the allosteric.
4) When can the bonding radius of an atom be larger than its atomic? I know Cl- is larger than Cl, but thats not the bonding radius.
Finally, this is from Kaplan-
5) Which of the following is the most stable carbanion? (C-)
Ph = Phenyl
a) (Ph)3C-
b) (Ph)2HC-
c) PhH2C-
d) H3C-
e) (CH3)3C-
I chose d, since a carbanion will be stabilized by something that withdraws electrons (also an activating substituent btw). Since all of those things donate electrons more then H, I chose D. The correct answer is A, because of resonance. The problem is, Im failing to see the resonance there. I can pop the - charge on the phenyl rings, but I cant figure out where to throw the existing bonds.
Thoughts?
Thanks
Whit
2) Do plant cells have centrioles? I thought no...
3) During competitive inhibition, the inhibitor can bind to the substrate site, OR the allosteric site, correct? With non-comp- its just the allosteric.
4) When can the bonding radius of an atom be larger than its atomic? I know Cl- is larger than Cl, but thats not the bonding radius.
Finally, this is from Kaplan-
5) Which of the following is the most stable carbanion? (C-)
Ph = Phenyl
a) (Ph)3C-
b) (Ph)2HC-
c) PhH2C-
d) H3C-
e) (CH3)3C-
I chose d, since a carbanion will be stabilized by something that withdraws electrons (also an activating substituent btw). Since all of those things donate electrons more then H, I chose D. The correct answer is A, because of resonance. The problem is, Im failing to see the resonance there. I can pop the - charge on the phenyl rings, but I cant figure out where to throw the existing bonds.
Thoughts?
Thanks
Whit