TBR light that hits an interface in a perpendicular fashion

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We are given a figure of a half-cylinder with a point a at the top of the half cylinder. Light is transmitted through a half cylinder and the beam was allowed to strike a semi-circular screen.

Question asks : Light that initiates from point a in the figure:
A- will always strike the middle of the screen
B- doesn't leave the half-cylinder disk
C- splits to strike the screen at multiple points
D- slows when leaving the disk and entering air.

Answer is A
which does not make sense to me. If Light is hitting the cylinder of different material than air then n is bigger than air. so if it hits the cylinder with an angle of 90 degrees then

n*sin90= nair* sin angle hits the screen

so then for them to be equal the angle can't be 90!


Their explanation is " for light that strikes an interface in a perpendicular fashion it's speed will change but there will be no change in the orientation of the rays"


Thanks a lot!

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You're forgetting the definition of theta. Theta is always defined as the angle relative to the normal. Therefore, Snell's law becomes n1*sin(0) = n2*sin(theta2). Sin(0) = 0. Thus, no matter what n1 and n2 are, the only possible results for theta 2 are 0 degrees and 180 degrees. One of those doesn't make sense, which leaves you with the correct answer.
 
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You're forgetting the definition of theta. Theta is always defined as the angle relative to the normal. Therefore, Snell's law becomes n1*sin(0) = n2*sin(theta2). Sin(0) = 0. Thus, no matter what n1 and n2 are, the only possible results for theta 2 are 0 degrees and 180 degrees. One of those doesn't make sense, which leaves you with the correct answer.

Thank you so much!
 
You're forgetting the definition of theta. Theta is always defined as the angle relative to the normal. Therefore, Snell's law becomes n1*sin(0) = n2*sin(theta2). Sin(0) = 0. Thus, no matter what n1 and n2 are, the only possible results for theta 2 are 0 degrees and 180 degrees. One of those doesn't make sense, which leaves you with the correct answer.
What is the normal exactly? Can you draw it? Thank you
 
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